Integrand size = 22, antiderivative size = 50 \[ \int \frac {1-2 x^2}{1-2 x^2+4 x^4} \, dx=-\frac {\log \left (1-\sqrt {6} x+2 x^2\right )}{2 \sqrt {6}}+\frac {\log \left (1+\sqrt {6} x+2 x^2\right )}{2 \sqrt {6}} \]
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Time = 0.02 (sec) , antiderivative size = 50, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.091, Rules used = {1178, 642} \[ \int \frac {1-2 x^2}{1-2 x^2+4 x^4} \, dx=\frac {\log \left (2 x^2+\sqrt {6} x+1\right )}{2 \sqrt {6}}-\frac {\log \left (2 x^2-\sqrt {6} x+1\right )}{2 \sqrt {6}} \]
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Rule 642
Rule 1178
Rubi steps \begin{align*} \text {integral}& = -\frac {\int \frac {\sqrt {\frac {3}{2}}+2 x}{-\frac {1}{2}-\sqrt {\frac {3}{2}} x-x^2} \, dx}{2 \sqrt {6}}-\frac {\int \frac {\sqrt {\frac {3}{2}}-2 x}{-\frac {1}{2}+\sqrt {\frac {3}{2}} x-x^2} \, dx}{2 \sqrt {6}} \\ & = -\frac {\log \left (1-\sqrt {6} x+2 x^2\right )}{2 \sqrt {6}}+\frac {\log \left (1+\sqrt {6} x+2 x^2\right )}{2 \sqrt {6}} \\ \end{align*}
Time = 0.02 (sec) , antiderivative size = 42, normalized size of antiderivative = 0.84 \[ \int \frac {1-2 x^2}{1-2 x^2+4 x^4} \, dx=\frac {-\log \left (-1+\sqrt {6} x-2 x^2\right )+\log \left (1+\sqrt {6} x+2 x^2\right )}{2 \sqrt {6}} \]
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Time = 0.04 (sec) , antiderivative size = 39, normalized size of antiderivative = 0.78
method | result | size |
default | \(-\frac {\ln \left (1+2 x^{2}-x \sqrt {6}\right ) \sqrt {6}}{12}+\frac {\ln \left (1+2 x^{2}+x \sqrt {6}\right ) \sqrt {6}}{12}\) | \(39\) |
risch | \(-\frac {\ln \left (1+2 x^{2}-x \sqrt {6}\right ) \sqrt {6}}{12}+\frac {\ln \left (1+2 x^{2}+x \sqrt {6}\right ) \sqrt {6}}{12}\) | \(39\) |
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Time = 0.27 (sec) , antiderivative size = 45, normalized size of antiderivative = 0.90 \[ \int \frac {1-2 x^2}{1-2 x^2+4 x^4} \, dx=\frac {1}{12} \, \sqrt {6} \log \left (\frac {4 \, x^{4} + 10 \, x^{2} + 2 \, \sqrt {6} {\left (2 \, x^{3} + x\right )} + 1}{4 \, x^{4} - 2 \, x^{2} + 1}\right ) \]
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Time = 0.05 (sec) , antiderivative size = 46, normalized size of antiderivative = 0.92 \[ \int \frac {1-2 x^2}{1-2 x^2+4 x^4} \, dx=- \frac {\sqrt {6} \log {\left (x^{2} - \frac {\sqrt {6} x}{2} + \frac {1}{2} \right )}}{12} + \frac {\sqrt {6} \log {\left (x^{2} + \frac {\sqrt {6} x}{2} + \frac {1}{2} \right )}}{12} \]
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\[ \int \frac {1-2 x^2}{1-2 x^2+4 x^4} \, dx=\int { -\frac {2 \, x^{2} - 1}{4 \, x^{4} - 2 \, x^{2} + 1} \,d x } \]
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Time = 0.27 (sec) , antiderivative size = 40, normalized size of antiderivative = 0.80 \[ \int \frac {1-2 x^2}{1-2 x^2+4 x^4} \, dx=\frac {1}{12} \, \sqrt {6} \log \left (x^{2} + \sqrt {3} \left (\frac {1}{4}\right )^{\frac {1}{4}} x + \frac {1}{2}\right ) - \frac {1}{12} \, \sqrt {6} \log \left (x^{2} - \sqrt {3} \left (\frac {1}{4}\right )^{\frac {1}{4}} x + \frac {1}{2}\right ) \]
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Time = 0.07 (sec) , antiderivative size = 20, normalized size of antiderivative = 0.40 \[ \int \frac {1-2 x^2}{1-2 x^2+4 x^4} \, dx=\frac {\sqrt {6}\,\mathrm {atanh}\left (\frac {\sqrt {6}\,x}{2\,x^2+1}\right )}{6} \]
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